1300510200001 has 4 divisors (see below), whose sum is σ = 1301401572400. Its totient is φ = 1299618827604.

The previous prime is 1300510199927. The next prime is 1300510200013. The reversal of 1300510200001 is 1000020150031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1300510200001 - 2¹⁵ = 1300510167233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1300510200401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 445684011 + ... + 445686928.

It is an arithmetic number, because the mean of its divisors is an integer number (325350393100).

Almost surely, 2^{1300510200001} is an apocalyptic number.

It is an amenable number.

1300510200001 is a deficient number, since it is larger than the sum of its proper divisors (891372399).

1300510200001 is an equidigital number, since it uses as much as digits as its factorization.

1300510200001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 891372398.

The product of its (nonzero) digits is 30, while the sum is 13.

Adding to 1300510200001 its reverse (1000020150031), we get a palindrome (2300530350032).

The spelling of 1300510200001 in words is "one trillion, three hundred billion, five hundred ten million, two hundred thousand, one".