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13005445345 = 531139603641
BaseRepresentation
bin11000001110010111…
…10101100011100001
31020120101001002001221
430013023311203201
5203113343222340
65550303455041
7640200314164
oct140713654341
936511032057
1013005445345
115574264642
12262b5b7481
1312c355a3b9
148b5385adb
15511b7a44a
hex3072f58e1

13005445345 has 16 divisors (see below), whose sum is σ = 16225896960. Its totient is φ = 9996278400.

The previous prime is 13005445319. The next prime is 13005445361. The reversal of 13005445345 is 54354450031.

13005445345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13005445345 - 227 = 12871227617 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13005445345.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280276 + ... + 323365.

It is an arithmetic number, because the mean of its divisors is an integer number (1014118560).

Almost surely, 213005445345 is an apocalyptic number.

It is an amenable number.

13005445345 is a deficient number, since it is larger than the sum of its proper divisors (3220451615).

13005445345 is a wasteful number, since it uses less digits than its factorization.

13005445345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 603816.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 13005445345 its reverse (54354450031), we get a palindrome (67359895376).

The spelling of 13005445345 in words is "thirteen billion, five million, four hundred forty-five thousand, three hundred forty-five".

Divisors: 1 5 31 139 155 695 4309 21545 603641 3018205 18712871 83906099 93564355 419530495 2601089069 13005445345