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130054513241 = 472767117303
BaseRepresentation
bin111100100011111011…
…0100110001001011001
3110102200201111210201202
41321013312212021121
54112322423410431
6135425103323545
712252605060042
oct1710766461131
9412621453652
10130054513241
11501794227a4
1221256bb05b5
13c3582802a3
14641a8198c9
1535b2a308cb
hex1e47da6259

130054513241 has 4 divisors (see below), whose sum is σ = 132821630592. Its totient is φ = 127287395892.

The previous prime is 130054513229. The next prime is 130054513243. The reversal of 130054513241 is 142315450031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 142315450031 = 190979745189.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130054513241 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130054513243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1383558605 + ... + 1383558698.

It is an arithmetic number, because the mean of its divisors is an integer number (33205407648).

Almost surely, 2130054513241 is an apocalyptic number.

It is an amenable number.

130054513241 is a deficient number, since it is larger than the sum of its proper divisors (2767117351).

130054513241 is an equidigital number, since it uses as much as digits as its factorization.

130054513241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2767117350.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 130054513241 its reverse (142315450031), we get a palindrome (272369963272).

The spelling of 130054513241 in words is "one hundred thirty billion, fifty-four million, five hundred thirteen thousand, two hundred forty-one".

Divisors: 1 47 2767117303 130054513241