13005564535 has 4 divisors (see below), whose sum is σ = 15606677448. Its totient is φ = 10404451624.

The previous prime is 13005564529. The next prime is 13005564541. The reversal of 13005564535 is 53546550031.

13005564535 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13005564529) and next prime (13005564541).

It is a cyclic number.

It is not a de Polignac number, because 13005564535 - 2¹⁵ = 13005531767 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13005564494 and 13005564503.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1300556449 + ... + 1300556458.

It is an arithmetic number, because the mean of its divisors is an integer number (3901669362).

Almost surely, 2^13005564535 is an apocalyptic number.

13005564535 is a deficient number, since it is larger than the sum of its proper divisors (2601112913).

13005564535 is an equidigital number, since it uses as much as digits as its factorization.

13005564535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2601112912.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 13005564535 in words is "thirteen billion, five million, five hundred sixty-four thousand, five hundred thirty-five".