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13006406143 = 1091045711411
BaseRepresentation
bin11000001110011111…
…00000000111111111
31020120102211220001001
430013033200013333
5203114114444033
65550340231131
7640211425303
oct140717400777
936512756031
1013006406143
115574860495
12262b99b4a7
1312c3805813
148b5555d03
15511cb9e7d
hex3073e01ff

13006406143 has 8 divisors (see below), whose sum is σ = 13128136560. Its totient is φ = 12884719680.

The previous prime is 13006406081. The next prime is 13006406191. The reversal of 13006406143 is 34160460031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13006406143 - 213 = 13006397951 is a prime.

It is a Duffinian number.

It is a zygodrome in base 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13006404143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1134108 + ... + 1145518.

It is an arithmetic number, because the mean of its divisors is an integer number (1641017070).

Almost surely, 213006406143 is an apocalyptic number.

13006406143 is a deficient number, since it is larger than the sum of its proper divisors (121730417).

13006406143 is a wasteful number, since it uses less digits than its factorization.

13006406143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21977.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13006406143 its reverse (34160460031), we get a palindrome (47166866174).

The spelling of 13006406143 in words is "thirteen billion, six million, four hundred six thousand, one hundred forty-three".

Divisors: 1 109 10457 11411 1139813 1243799 119324827 13006406143