130064141335 has 4 divisors (see below), whose sum is σ = 156076969608. Its totient is φ = 104051313064.

The previous prime is 130064141329. The next prime is 130064141377. The reversal of 130064141335 is 533141460031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130064141335 - 2²¹ = 130062044183 is a prime.

It is a super-2 number, since 2×130064141335² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130064141297 and 130064141306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13006414129 + ... + 13006414138.

It is an arithmetic number, because the mean of its divisors is an integer number (39019242402).

Almost surely, 2^130064141335 is an apocalyptic number.

130064141335 is a deficient number, since it is larger than the sum of its proper divisors (26012828273).

130064141335 is an equidigital number, since it uses as much as digits as its factorization.

130064141335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26012828272.

The product of its (nonzero) digits is 12960, while the sum is 31.

The spelling of 130064141335 in words is "one hundred thirty billion, sixty-four million, one hundred forty-one thousand, three hundred thirty-five".