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130064655535 = 5112923040683
BaseRepresentation
bin111100100100001110…
…1010010010010101111
3110102201102121002100021
41321020131102102233
54112333022434120
6135430104543011
712253060221313
oct1711035222257
9412642532307
10130064655535
115018411a861
122125a481a67
13c35a3c1849
14641bcd9b43
1535b3885aaa
hex1e487524af

130064655535 has 8 divisors (see below), whose sum is σ = 156215837520. Its totient is φ = 103959557184.

The previous prime is 130064655527. The next prime is 130064655599. The reversal of 130064655535 is 535556460031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130064655535 - 23 = 130064655527 is a prime.

It is a super-2 number, since 2×1300646555352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130064655491 and 130064655500.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11514697 + ... + 11525986.

It is an arithmetic number, because the mean of its divisors is an integer number (19526979690).

Almost surely, 2130064655535 is an apocalyptic number.

130064655535 is a deficient number, since it is larger than the sum of its proper divisors (26151181985).

130064655535 is a wasteful number, since it uses less digits than its factorization.

130064655535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23041817.

The product of its (nonzero) digits is 810000, while the sum is 43.

The spelling of 130064655535 in words is "one hundred thirty billion, sixty-four million, six hundred fifty-five thousand, five hundred thirty-five".

Divisors: 1 5 1129 5645 23040683 115203415 26012931107 130064655535