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130073635 = 526014727
BaseRepresentation
bin1111100000011…
…00010000100011
3100001202102111001
413300030100203
5231244324020
620523532431
73136415266
oct760142043
9301672431
10130073635
116747227a
123768a117
1320c43163
14133bccdd
15b64550a
hex7c0c423

130073635 has 4 divisors (see below), whose sum is σ = 156088368. Its totient is φ = 104058904.

The previous prime is 130073627. The next prime is 130073707. The reversal of 130073635 is 536370031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 536370031 = 1319406649.

It is a cyclic number.

It is not a de Polignac number, because 130073635 - 23 = 130073627 is a prime.

It is a super-2 number, since 2×1300736352 = 33838301044226450, which contains 22 as substring.

It is a Duffinian number.

It is a plaindrome in base 14.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13007359 + ... + 13007368.

It is an arithmetic number, because the mean of its divisors is an integer number (39022092).

Almost surely, 2130073635 is an apocalyptic number.

130073635 is a deficient number, since it is larger than the sum of its proper divisors (26014733).

130073635 is an equidigital number, since it uses as much as digits as its factorization.

130073635 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26014732.

The product of its (nonzero) digits is 5670, while the sum is 28.

The square root of 130073635 is about 11404.9829022230. The cubic root of 130073635 is about 506.6753300015.

The spelling of 130073635 in words is "one hundred thirty million, seventy-three thousand, six hundred thirty-five".

Divisors: 1 5 26014727 130073635