130100011312301 has 4 divisors (see below), whose sum is σ = 130217962366272. Its totient is φ = 129982060258332.

The previous prime is 130100011312199. The next prime is 130100011312331. The reversal of 130100011312301 is 103213110001031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130100011312301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130100011312301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130100011312331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58975525331 + ... + 58975527536.

It is an arithmetic number, because the mean of its divisors is an integer number (32554490591568).

Almost surely, 2^{130100011312301} is an apocalyptic number.

It is an amenable number.

130100011312301 is a deficient number, since it is larger than the sum of its proper divisors (117951053971).

130100011312301 is a wasteful number, since it uses less digits than its factorization.

130100011312301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117951053970.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 130100011312301 its reverse (103213110001031), we get a palindrome (233313121313332).

The spelling of 130100011312301 in words is "one hundred thirty trillion, one hundred billion, eleven million, three hundred twelve thousand, three hundred one".