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1301001131001 = 311133032636669
BaseRepresentation
bin10010111011101001101…
…101011101001111111001
311121101010000011011210010
4102323221231131033321
5132303422242143001
62433401025212133
7162665010102555
oct22735155351771
94541100134703
101301001131001
1146182a248790
12190186791049
13958b763c350
1446d7c50c865
1523c96c7b8d6
hex12ee9b5d3f9

1301001131001 has 16 divisors (see below), whose sum is σ = 2037931842240. Its totient is φ = 727832800320.

The previous prime is 1301001130999. The next prime is 1301001131039. The reversal of 1301001131001 is 1001311001031.

It is not a de Polignac number, because 1301001131001 - 21 = 1301001130999 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1301001131071) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1516317906 + ... + 1516318763.

It is an arithmetic number, because the mean of its divisors is an integer number (127370740140).

Almost surely, 21301001131001 is an apocalyptic number.

1301001131001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1301001131001 is a deficient number, since it is larger than the sum of its proper divisors (736930711239).

1301001131001 is a wasteful number, since it uses less digits than its factorization.

1301001131001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3032636696.

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 1301001131001 its reverse (1001311001031), we get a palindrome (2302312132032).

The spelling of 1301001131001 in words is "one trillion, three hundred one billion, one million, one hundred thirty-one thousand, one".

Divisors: 1 3 11 13 33 39 143 429 3032636669 9097910007 33359003359 39424276697 100077010077 118272830091 433667043667 1301001131001