Base | Representation |
---|---|
bin | 11101100101001101001011… |
… | …000010011101111000010011 |
3 | 122001122110010120211220210021 |
4 | 131211031023002131320103 |
5 | 114023030013001113021 |
6 | 1140411100021244311 |
7 | 36255265042550560 |
oct | 3545151302357023 |
9 | 561573116756707 |
10 | 130100113301011 |
11 | 384aa16a28a027 |
12 | 12712334863697 |
13 | 57795076b4639 |
14 | 241ac442b3867 |
15 | 1009308713c41 |
hex | 76534b09de13 |
130100113301011 has 8 divisors (see below), whose sum is σ = 151491237051744. Its totient is φ = 109410337870080.
The previous prime is 130100113300999. The next prime is 130100113301089. The reversal of 130100113301011 is 110103311001031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130100113301011 - 211 = 130100113298963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130100113304011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175337079550 + ... + 175337080291.
It is an arithmetic number, because the mean of its divisors is an integer number (18936404631468).
Almost surely, 2130100113301011 is an apocalyptic number.
130100113301011 is a deficient number, since it is larger than the sum of its proper divisors (21391123750733).
130100113301011 is an equidigital number, since it uses as much as digits as its factorization.
130100113301011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350674159901.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 130100113301011 its reverse (110103311001031), we get a palindrome (240203424302042).
The spelling of 130100113301011 in words is "one hundred thirty trillion, one hundred billion, one hundred thirteen million, three hundred one thousand, eleven".
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