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1301001200223 = 3433667066741
BaseRepresentation
bin10010111011101001101…
…101101110001001011111
311121101010000021200201220
4102323221231232021133
5132303422301401343
62433401030504423
7162665010511434
oct22735155561137
94541100250656
101301001200223
1146182a29579a
12190186805113
13958b76649ca
1446d7c529b8b
1523c96c92183
hex12ee9b6e25f

1301001200223 has 4 divisors (see below), whose sum is σ = 1734668266968. Its totient is φ = 867334133480.

The previous prime is 1301001200203. The next prime is 1301001200249. The reversal of 1301001200223 is 3220021001031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301001200223 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301001200203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216833533368 + ... + 216833533373.

It is an arithmetic number, because the mean of its divisors is an integer number (433667066742).

Almost surely, 21301001200223 is an apocalyptic number.

1301001200223 is a deficient number, since it is larger than the sum of its proper divisors (433667066745).

1301001200223 is an equidigital number, since it uses as much as digits as its factorization.

1301001200223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 433667066744.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1301001200223 its reverse (3220021001031), we get a palindrome (4521022201254).

The spelling of 1301001200223 in words is "one trillion, three hundred one billion, one million, two hundred thousand, two hundred twenty-three".

Divisors: 1 3 433667066741 1301001200223