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1301005240301 = 13100077326177
BaseRepresentation
bin10010111011101001111…
…101001000011111101101
311121101010021212221200102
4102323221331020133231
5132303424320142201
62433401253240445
7162665060036204
oct22735175103755
94541107787612
101301005240301
114618315a50a8
12190188033125
13958b844a8a0
1446d7cc9c23b
1523c972de26b
hex12ee9f487ed

1301005240301 has 4 divisors (see below), whose sum is σ = 1401082566492. Its totient is φ = 1200927914112.

The previous prime is 1301005240291. The next prime is 1301005240307. The reversal of 1301005240301 is 1030425001031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 166279635076 + 1134725605225 = 407774^2 + 1065235^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1301005240301 is a prime.

It is a super-2 number, since 2×13010052403012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301005240307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50038663076 + ... + 50038663101.

It is an arithmetic number, because the mean of its divisors is an integer number (350270641623).

Almost surely, 21301005240301 is an apocalyptic number.

It is an amenable number.

1301005240301 is a deficient number, since it is larger than the sum of its proper divisors (100077326191).

1301005240301 is a wasteful number, since it uses less digits than its factorization.

1301005240301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100077326190.

The product of its (nonzero) digits is 360, while the sum is 20.

The spelling of 1301005240301 in words is "one trillion, three hundred one billion, five million, two hundred forty thousand, three hundred one".

Divisors: 1 13 100077326177 1301005240301