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13010094720 = 273357591823
BaseRepresentation
bin11000001110111011…
…00100101010000000
31020120200210021211000
430013131210222000
5203121041012340
65550551252000
7640254660210
oct140735445200
936520707730
1013010094720
11557694a7a7
12263107a000
1312c44c76cc
148b5c36240
15512297d30
hex307764a80

13010094720 has 512 divisors, whose sum is σ = 53581824000. Its totient is φ = 2921730048.

The previous prime is 13010094683. The next prime is 13010094731. The reversal of 13010094720 is 2749001031.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7135729 + ... + 7137551.

It is an arithmetic number, because the mean of its divisors is an integer number (104652000).

Almost surely, 213010094720 is an apocalyptic number.

13010094720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13010094720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26790912000).

13010094720 is an abundant number, since it is smaller than the sum of its proper divisors (40571729280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13010094720 is a wasteful number, since it uses less digits than its factorization.

13010094720 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1917 (or 1899 counting only the distinct ones).

The product of its (nonzero) digits is 1512, while the sum is 27.

Adding to 13010094720 its reverse (2749001031), we get a palindrome (15759095751).

The spelling of 13010094720 in words is "thirteen billion, ten million, ninety-four thousand, seven hundred twenty".