Base | Representation |
---|---|
bin | 11101100101001101111111… |
… | …111000111101001000000010 |
3 | 122001122112102101022220010122 |
4 | 131211031333320331020002 |
5 | 114023033322000000002 |
6 | 1140411324014300242 |
7 | 36255326030431043 |
oct | 3545157770751002 |
9 | 561575371286118 |
10 | 130101000000002 |
11 | 384aa584857109 |
12 | 127125417b7682 |
13 | 5779619301ab5 |
14 | 241acc9d6a8ca |
15 | 100935b4b46a2 |
hex | 76537fe3d202 |
130101000000002 has 4 divisors (see below), whose sum is σ = 195151500000006. Its totient is φ = 65050500000000.
The previous prime is 130100999999981. The next prime is 130101000000011. The reversal of 130101000000002 is 200000000101031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 113421200703721 + 16679799296281 = 10649939^2 + 4084091^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32525249999999 + ... + 32525250000002.
Almost surely, 2130101000000002 is an apocalyptic number.
130101000000002 is a deficient number, since it is larger than the sum of its proper divisors (65050500000004).
130101000000002 is an equidigital number, since it uses as much as digits as its factorization.
130101000000002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65050500000003.
The product of its (nonzero) digits is 6, while the sum is 8.
Adding to 130101000000002 its reverse (200000000101031), we get a palindrome (330101000101033).
The spelling of 130101000000002 in words is "one hundred thirty trillion, one hundred one billion, two", and thus it is an aban number.
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