Base | Representation |
---|---|
bin | 10010111011101010010… |
… | …000011110100010010000 |
3 | 11121101010122102120210122 |
4 | 102323222100132202100 |
5 | 132303432114430222 |
6 | 2433401554045412 |
7 | 162665151116405 |
oct | 22735220364220 |
9 | 4541118376718 |
10 | 1301010311312 |
11 | 461834449018 |
12 | 190189879868 |
13 | 958b9504a9a |
14 | 46d7d81c2ac |
15 | 23c97991a42 |
hex | 12eea41e890 |
1301010311312 has 40 divisors (see below), whose sum is σ = 2607804990840. Its totient is φ = 628031416320.
The previous prime is 1301010311269. The next prime is 1301010311327. The reversal of 1301010311312 is 2131130101031.
It can be written as a sum of positive squares in 4 ways, for example, as 414241555456 + 886768755856 = 643616^2 + 941684^2 .
It is a super-2 number, since 2×13010103113122 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7402568 + ... + 7576280.
It is an arithmetic number, because the mean of its divisors is an integer number (65195124771).
Almost surely, 21301010311312 is an apocalyptic number.
It is an amenable number.
1301010311312 is an abundant number, since it is smaller than the sum of its proper divisors (1306794679528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1301010311312 is a wasteful number, since it uses less digits than its factorization.
1301010311312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189891 (or 189885 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1301010311312 its reverse (2131130101031), we get a palindrome (3432140412343).
The spelling of 1301010311312 in words is "one trillion, three hundred one billion, ten million, three hundred eleven thousand, three hundred twelve".
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