Base | Representation |
---|---|
bin | 10010111011101010010… |
… | …011111100011011110011 |
3 | 11121101010201010202120120 |
4 | 102323222103330123303 |
5 | 132303432333021321 |
6 | 2433402025341323 |
7 | 162665161623303 |
oct | 22735223743363 |
9 | 4541121122516 |
10 | 1301011220211 |
11 | 461834a0997a |
12 | 19018a037843 |
13 | 958b97626b1 |
14 | 46d7d9b7603 |
15 | 23c97ac0ec6 |
hex | 12eea4fc6f3 |
1301011220211 has 8 divisors (see below), whose sum is σ = 1735682604240. Its totient is φ = 866840324832.
The previous prime is 1301011220137. The next prime is 1301011220263. The reversal of 1301011220211 is 1120221101031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-1301011220211 is a prime.
It is a super-2 number, since 2×13010112202112 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1301011220711) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125116096 + ... + 125126493.
It is an arithmetic number, because the mean of its divisors is an integer number (216960325530).
Almost surely, 21301011220211 is an apocalyptic number.
1301011220211 is a deficient number, since it is larger than the sum of its proper divisors (434671384029).
1301011220211 is a wasteful number, since it uses less digits than its factorization.
1301011220211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 250244325.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1301011220211 its reverse (1120221101031), we get a palindrome (2421232321242).
The spelling of 1301011220211 in words is "one trillion, three hundred one billion, eleven million, two hundred twenty thousand, two hundred eleven".
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