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13010113200011 = 21487605487653
BaseRepresentation
bin1011110101010010011100…
…1011001111111110001011
31201001202101011021022121212
42331110213023033332023
53201124202434400021
643400432525323335
72511643506363464
oct275244713177613
951052334238555
1013010113200011
114166615801634
12156154470654b
13734b04c5b635
1432d99b213d6b
1517865245585b
hexbd5272cff8b

13010113200011 has 4 divisors (see below), whose sum is σ = 13010718709152. Its totient is φ = 13009507690872.

The previous prime is 13010113200001. The next prime is 13010113200079. The reversal of 13010113200011 is 11000231101031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13010113200011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13010113200001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302722340 + ... + 302765313.

It is an arithmetic number, because the mean of its divisors is an integer number (3252679677288).

Almost surely, 213010113200011 is an apocalyptic number.

13010113200011 is a deficient number, since it is larger than the sum of its proper divisors (605509141).

13010113200011 is an equidigital number, since it uses as much as digits as its factorization.

13010113200011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 605509140.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 13010113200011 its reverse (11000231101031), we get a palindrome (24010344301042).

The spelling of 13010113200011 in words is "thirteen trillion, ten billion, one hundred thirteen million, two hundred thousand, eleven".

Divisors: 1 21487 605487653 13010113200011