Base | Representation |
---|---|
bin | 10010111011101010010… |
… | …111011000000111000001 |
3 | 11121101010202211110212010 |
4 | 102323222113120013001 |
5 | 132303433100320001 |
6 | 2433402100523133 |
7 | 162665202361506 |
oct | 22735227300701 |
9 | 4541122743763 |
10 | 1301012120001 |
11 | 461835473a00 |
12 | 19018a3b04a9 |
13 | 958b99b9109 |
14 | 46d7db6d4ad |
15 | 23c97bec8d6 |
hex | 12eea5d81c1 |
1301012120001 has 24 divisors (see below), whose sum is σ = 1937975183872. Its totient is φ = 775566079200.
The previous prime is 1301012119997. The next prime is 1301012120017. The reversal of 1301012120001 is 1000212101031.
It is not a de Polignac number, because 1301012120001 - 22 = 1301012119997 is a prime.
It is a super-3 number, since 3×13010121200013 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1301012120041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29355361 + ... + 29399646.
Almost surely, 21301012120001 is an apocalyptic number.
1301012120001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1301012120001 is a deficient number, since it is larger than the sum of its proper divisors (636963063871).
1301012120001 is a wasteful number, since it uses less digits than its factorization.
1301012120001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58755093 (or 58755082 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 1301012120001 its reverse (1000212101031), we get a palindrome (2301224221032).
The spelling of 1301012120001 in words is "one trillion, three hundred one billion, twelve million, one hundred twenty thousand, one".
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