Base | Representation |
---|---|
bin | 10010111011101010011… |
… | …011001010001000000111 |
3 | 11121101010211200211200000 |
4 | 102323222123022020013 |
5 | 132303433324030203 |
6 | 2433402134052343 |
7 | 162665213660553 |
oct | 22735233121007 |
9 | 4541124624600 |
10 | 1301013111303 |
11 | 461835a90764 |
12 | 19018a7aa0b3 |
13 | 958b9c75399 |
14 | 46d7dd4a863 |
15 | 23c97d464a3 |
hex | 12eea6ca207 |
1301013111303 has 12 divisors (see below), whose sum is σ = 1948842685608. Its totient is φ = 867342074040.
The previous prime is 1301013111271. The next prime is 1301013111317. The reversal of 1301013111303 is 3031113101031.
It is not a de Polignac number, because 1301013111303 - 25 = 1301013111271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1301013111403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2676981468 + ... + 2676981953.
It is an arithmetic number, because the mean of its divisors is an integer number (162403557134).
Almost surely, 21301013111303 is an apocalyptic number.
1301013111303 is a deficient number, since it is larger than the sum of its proper divisors (647829574305).
1301013111303 is an frugal number, since it uses more digits than its factorization.
1301013111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5353963436 (or 5353963424 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 18.
Adding to 1301013111303 its reverse (3031113101031), we get a palindrome (4332126212334).
The spelling of 1301013111303 in words is "one trillion, three hundred one billion, thirteen million, one hundred eleven thousand, three hundred three".
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