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130102011023 = 1012137602779
BaseRepresentation
bin111100100101010101…
…1110010010010001111
3110102211000212221102212
41321022223302102033
54112422103323043
6135433521341035
712254022563405
oct1711253622217
9412730787385
10130102011023
11501a3214566
122126aa9777b
13c36507079a
146422c61475
1535b6cb4018
hex1e4aaf248f

130102011023 has 8 divisors (see below), whose sum is σ = 131451851280. Its totient is φ = 128753380800.

The previous prime is 130102011019. The next prime is 130102011031. The reversal of 130102011023 is 320110201031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130102011023 - 22 = 130102011019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130102010989 and 130102011007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130102011223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85553 + ... + 517226.

It is an arithmetic number, because the mean of its divisors is an integer number (16431481410).

Almost surely, 2130102011023 is an apocalyptic number.

130102011023 is a deficient number, since it is larger than the sum of its proper divisors (1349840257).

130102011023 is a wasteful number, since it uses less digits than its factorization.

130102011023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605017.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 130102011023 its reverse (320110201031), we get a palindrome (450212212054).

The spelling of 130102011023 in words is "one hundred thirty billion, one hundred two million, eleven thousand, twenty-three".

Divisors: 1 101 2137 215837 602779 60880679 1288138723 130102011023