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130102212021 = 343367404007
BaseRepresentation
bin111100100101010110…
…0100011010110110101
3110102211001021011011020
41321022230203112311
54112422131241041
6135433525531353
712254024361405
oct1711254432665
9412731234136
10130102212021
11501a3341581
122126ab73b59
13c365111112
146422cb4805
1535b6d03866
hex1e4ab235b5

130102212021 has 4 divisors (see below), whose sum is σ = 173469616032. Its totient is φ = 86734808012.

The previous prime is 130102212011. The next prime is 130102212041. The reversal of 130102212021 is 120212201031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130102212021 - 214 = 130102195637 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130102212011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21683702001 + ... + 21683702006.

It is an arithmetic number, because the mean of its divisors is an integer number (43367404008).

Almost surely, 2130102212021 is an apocalyptic number.

It is an amenable number.

130102212021 is a deficient number, since it is larger than the sum of its proper divisors (43367404011).

130102212021 is an equidigital number, since it uses as much as digits as its factorization.

130102212021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43367404010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 130102212021 its reverse (120212201031), we get a palindrome (250314413052).

The spelling of 130102212021 in words is "one hundred thirty billion, one hundred two million, two hundred twelve thousand, twenty-one".

Divisors: 1 3 43367404007 130102212021