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13010230113 = 343671505291
BaseRepresentation
bin11000001110111100…
…00101101101100001
31020120201001011112120
430013132011231201
5203121104330423
65550554214453
7640256063016
oct140736055541
936521034476
1013010230113
115576a324a1
122631124429
1312c454421a
148b5c6d70d
155122c2ee3
hex307785b61

13010230113 has 16 divisors (see below), whose sum is σ = 18015334656. Its totient is φ = 8345327760.

The previous prime is 13010230073. The next prime is 13010230127. The reversal of 13010230113 is 31103201031.

13010230113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13010230113 - 216 = 13010164577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13010230092 and 13010230101.

It is not an unprimeable number, because it can be changed into a prime (13010230913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 744003 + ... + 761288.

It is an arithmetic number, because the mean of its divisors is an integer number (1125958416).

Almost surely, 213010230113 is an apocalyptic number.

It is an amenable number.

13010230113 is a deficient number, since it is larger than the sum of its proper divisors (5005104543).

13010230113 is a wasteful number, since it uses less digits than its factorization.

13010230113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1505404.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13010230113 its reverse (31103201031), we get a palindrome (44113431144).

The spelling of 13010230113 in words is "thirteen billion, ten million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 43 67 129 201 2881 8643 1505291 4515873 64727513 100854497 194182539 302563491 4336743371 13010230113