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130103032000 = 2653193127611
BaseRepresentation
bin111100100101010111…
…1101011100011000000
3110102211002210210221211
41321022233223203000
54112422334011000
6135433555255504
712254034345124
oct1711257534300
9412732723854
10130103032000
11501a3851647
122126b2aa594
13c36533a406
146423049584
1535b6e167ba
hex1e4abeb8c0

130103032000 has 224 divisors, whose sum is σ = 350111324160. Its totient is φ = 47710080000.

The previous prime is 130103031991. The next prime is 130103032013. The reversal of 130103032000 is 230301031.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4698195 + ... + 4725805.

Almost surely, 2130103032000 is an apocalyptic number.

130103032000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130103032000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (175055662080).

130103032000 is an abundant number, since it is smaller than the sum of its proper divisors (220008292160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130103032000 is a wasteful number, since it uses less digits than its factorization.

130103032000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27688 (or 27668 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 130103032000 its reverse (230301031), we get a palindrome (130333333031).

The spelling of 130103032000 in words is "one hundred thirty billion, one hundred three million, thirty-two thousand".