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13010403121 = 19684758059
BaseRepresentation
bin11000001110111101…
…01111111100110001
31020120201100221212021
430013132233330301
5203121130344441
65551002031441
7640260413302
oct140736577461
936521327767
1013010403121
115577040481
1226311a8581
1312c45a4bb1
148b5cb67a9
155123093d1
hex3077aff31

13010403121 has 4 divisors (see below), whose sum is σ = 13695161200. Its totient is φ = 12325645044.

The previous prime is 13010403103. The next prime is 13010403137. The reversal of 13010403121 is 12130401031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13010403121 - 227 = 12876185393 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13010403095 and 13010403104.

It is not an unprimeable number, because it can be changed into a prime (13010403191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342379011 + ... + 342379048.

It is an arithmetic number, because the mean of its divisors is an integer number (3423790300).

Almost surely, 213010403121 is an apocalyptic number.

It is an amenable number.

13010403121 is a deficient number, since it is larger than the sum of its proper divisors (684758079).

13010403121 is an equidigital number, since it uses as much as digits as its factorization.

13010403121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 684758078.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13010403121 its reverse (12130401031), we get a palindrome (25140804152).

The spelling of 13010403121 in words is "thirteen billion, ten million, four hundred three thousand, one hundred twenty-one".

Divisors: 1 19 684758059 13010403121