Base | Representation |
---|---|
bin | 11000001110111101… |
… | …01111111100110010 |
3 | 1020120201100221212022 |
4 | 30013132233330302 |
5 | 203121130344442 |
6 | 5551002031442 |
7 | 640260413303 |
oct | 140736577462 |
9 | 36521327768 |
10 | 13010403122 |
11 | 5577040482 |
12 | 26311a8582 |
13 | 12c45a4bb2 |
14 | 8b5cb67aa |
15 | 5123093d2 |
hex | 3077aff32 |
13010403122 has 4 divisors (see below), whose sum is σ = 19515604686. Its totient is φ = 6505201560.
The previous prime is 13010403103. The next prime is 13010403137. The reversal of 13010403122 is 22130401031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13009911721 + 491401 = 114061^2 + 701^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13010403122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3252600779 + ... + 3252600782.
Almost surely, 213010403122 is an apocalyptic number.
13010403122 is a deficient number, since it is larger than the sum of its proper divisors (6505201564).
13010403122 is an equidigital number, since it uses as much as digits as its factorization.
13010403122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6505201563.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13010403122 its reverse (22130401031), we get a palindrome (35140804153).
The spelling of 13010403122 in words is "thirteen billion, ten million, four hundred three thousand, one hundred twenty-two".
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