13011000113 has 4 divisors (see below), whose sum is σ = 13012422180. Its totient is φ = 13009578048.

The previous prime is 13011000103. The next prime is 13011000131. The reversal of 13011000113 is 31100011031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6867105424 + 6143894689 = 82868^2 + 78383^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011000113 - 2⁴ = 13011000097 is a prime.

It is a super-3 number, since 3×13011000113³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13011000094 and 13011000103.

It is not an unprimeable number, because it can be changed into a prime (13011000103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 697220 + ... + 715637.

It is an arithmetic number, because the mean of its divisors is an integer number (3253105545).

Almost surely, 2^13011000113 is an apocalyptic number.

It is an amenable number.

13011000113 is a deficient number, since it is larger than the sum of its proper divisors (1422067).

13011000113 is an equidigital number, since it uses as much as digits as its factorization.

13011000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1422066.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 13011000113 its reverse (31100011031), we get a palindrome (44111011144).

The spelling of 13011000113 in words is "thirteen billion, eleven million, one hundred thirteen", and thus it is an aban number.