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1301100055 = 5260220011
BaseRepresentation
bin100110110001101…
…0011011000010111
310100200020201201221
41031203103120113
510131040200210
6333035031211
744146111423
oct11543233027
93320221657
101301100055
11608489802
1230389b507
131797318b8
14c4b29b83
157935b1da
hex4d8d3617

1301100055 has 4 divisors (see below), whose sum is σ = 1561320072. Its totient is φ = 1040880040.

The previous prime is 1301100029. The next prime is 1301100089. The reversal of 1301100055 is 5500011031.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1301100055 - 25 = 1301100023 is a prime.

It is a super-2 number, since 2×13011000552 = 3385722706242006050, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130110001 + ... + 130110010.

It is an arithmetic number, because the mean of its divisors is an integer number (390330018).

Almost surely, 21301100055 is an apocalyptic number.

1301100055 is a deficient number, since it is larger than the sum of its proper divisors (260220017).

1301100055 is an equidigital number, since it uses as much as digits as its factorization.

1301100055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260220016.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 1301100055 is about 36070.7645469291. The cubic root of 1301100055 is about 1091.7006404231.

Adding to 1301100055 its reverse (5500011031), we get a palindrome (6801111086).

The spelling of 1301100055 in words is "one billion, three hundred one million, one hundred thousand, fifty-five".

Divisors: 1 5 260220011 1301100055