130110010011211 has 4 divisors (see below), whose sum is σ = 130110064471872. Its totient is φ = 130109955550552.

The previous prime is 130110010011181. The next prime is 130110010011227. The reversal of 130110010011211 is 112110010011031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130110010011211 - 2⁷ = 130110010011083 is a prime.

It is a super-2 number, since 2×130110010011211² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130110010011191 and 130110010011200.

It is not an unprimeable number, because it can be changed into a prime (130110010011811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23474011 + ... + 28482436.

It is an arithmetic number, because the mean of its divisors is an integer number (32527516117968).

Almost surely, 2^{130110010011211} is an apocalyptic number.

130110010011211 is a deficient number, since it is larger than the sum of its proper divisors (54460661).

130110010011211 is an equidigital number, since it uses as much as digits as its factorization.

130110010011211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54460660.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 130110010011211 its reverse (112110010011031), we get a palindrome (242220020022242).

The spelling of 130110010011211 in words is "one hundred thirty trillion, one hundred ten billion, ten million, eleven thousand, two hundred eleven".