Base | Representation |
---|---|
bin | 11001011111011010100101… |
… | …010100101000110110010111 |
3 | 112200221121112100122020000011 |
4 | 121133122211110220312113 |
5 | 104143302300030323111 |
6 | 1034234343321101051 |
7 | 32420452362632014 |
oct | 3137324524506627 |
9 | 480847470566004 |
10 | 112110010011031 |
11 | 327a3651a4956a |
12 | 106a7807627787 |
13 | 4a72c0c1292c6 |
14 | 1d9822105c70b |
15 | ce638a614021 |
hex | 65f6a5528d97 |
112110010011031 has 2 divisors, whose sum is σ = 112110010011032. Its totient is φ = 112110010011030.
The previous prime is 112110010010989. The next prime is 112110010011061. The reversal of 112110010011031 is 130110010011211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112110010011031 - 27 = 112110010010903 is a prime.
It is a super-3 number, since 3×1121100100110313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112110010011061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055005005515 + 56055005005516.
It is an arithmetic number, because the mean of its divisors is an integer number (56055005005516).
Almost surely, 2112110010011031 is an apocalyptic number.
112110010011031 is a deficient number, since it is larger than the sum of its proper divisors (1).
112110010011031 is an equidigital number, since it uses as much as digits as its factorization.
112110010011031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 112110010011031 its reverse (130110010011211), we get a palindrome (242220020022242).
The spelling of 112110010011031 in words is "one hundred twelve trillion, one hundred ten billion, ten million, eleven thousand, thirty-one".
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