13011002021 has 4 divisors (see below), whose sum is σ = 13065441600. Its totient is φ = 12956562444.

The previous prime is 13011001973. The next prime is 13011002023. The reversal of 13011002021 is 12020011031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011002021 - 2³⁰ = 11937260197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011001993 and 13011002011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011002023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27219431 + ... + 27219908.

It is an arithmetic number, because the mean of its divisors is an integer number (3266360400).

Almost surely, 2^13011002021 is an apocalyptic number.

It is an amenable number.

13011002021 is a deficient number, since it is larger than the sum of its proper divisors (54439579).

13011002021 is an equidigital number, since it uses as much as digits as its factorization.

13011002021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54439578.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 13011002021 its reverse (12020011031), we get a palindrome (25031013052).

The spelling of 13011002021 in words is "thirteen billion, eleven million, two thousand, twenty-one".