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1301102012011 = 4415572946623
BaseRepresentation
bin10010111011101111101…
…110010010011001101011
311121101101000222110111211
4102323233232102121223
5132304124103341021
62433415031333551
7163000343424364
oct22735756223153
94541330873454
101301102012011
1146188119111a
121901b45212b7
1395902500b59
1446d8ba8cb6b
1523ca0a573e1
hex12eefb9266b

1301102012011 has 4 divisors (see below), whose sum is σ = 1301105400192. Its totient is φ = 1301098623832.

The previous prime is 1301102011999. The next prime is 1301102012027. The reversal of 1301102012011 is 1102102011031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1301102012011 - 227 = 1300967794283 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301102011982 and 1301102012000.

It is not an unprimeable number, because it can be changed into a prime (1301102012911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1031755 + ... + 1914868.

It is an arithmetic number, because the mean of its divisors is an integer number (325276350048).

Almost surely, 21301102012011 is an apocalyptic number.

1301102012011 is a deficient number, since it is larger than the sum of its proper divisors (3388181).

1301102012011 is an equidigital number, since it uses as much as digits as its factorization.

1301102012011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3388180.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1301102012011 its reverse (1102102011031), we get a palindrome (2403204023042).

The spelling of 1301102012011 in words is "one trillion, three hundred one billion, one hundred two million, twelve thousand, eleven".

Divisors: 1 441557 2946623 1301102012011