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1301102100121 = 2356569656527
BaseRepresentation
bin10010111011101111101…
…110100111111010011001
311121101101001010221101011
4102323233232213322121
5132304124114200441
62433415033253521
7163000344242305
oct22735756477231
94541331127334
101301102100121
1146188124133a
121901b45642a1
1395902531ca5
1446d8bab2d05
1523ca0a73581
hex12eefba7e99

1301102100121 has 4 divisors (see below), whose sum is σ = 1357671756672. Its totient is φ = 1244532443572.

The previous prime is 1301102100071. The next prime is 1301102100143. The reversal of 1301102100121 is 1210012011031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301102100121 - 213 = 1301102091929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301102100721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28284828241 + ... + 28284828286.

It is an arithmetic number, because the mean of its divisors is an integer number (339417939168).

Almost surely, 21301102100121 is an apocalyptic number.

It is an amenable number.

1301102100121 is a deficient number, since it is larger than the sum of its proper divisors (56569656551).

1301102100121 is an equidigital number, since it uses as much as digits as its factorization.

1301102100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56569656550.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1301102100121 its reverse (1210012011031), we get a palindrome (2511114111152).

The spelling of 1301102100121 in words is "one trillion, three hundred one billion, one hundred two million, one hundred thousand, one hundred twenty-one".

Divisors: 1 23 56569656527 1301102100121