13011100113301 has 4 divisors (see below), whose sum is σ = 13011107330592. Its totient is φ = 13011092896012.

The previous prime is 13011100113259. The next prime is 13011100113337. The reversal of 13011100113301 is 10331100111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13011100113301 - 2²³ = 13011091724693 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011100113391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1645446 + ... + 5360008.

It is an arithmetic number, because the mean of its divisors is an integer number (3252776832648).

Almost surely, 2^{13011100113301} is an apocalyptic number.

It is an amenable number.

13011100113301 is a deficient number, since it is larger than the sum of its proper divisors (7217291).

13011100113301 is an equidigital number, since it uses as much as digits as its factorization.

13011100113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7217290.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13011100113301 its reverse (10331100111031), we get a palindrome (23342200224332).

The spelling of 13011100113301 in words is "thirteen trillion, eleven billion, one hundred million, one hundred thirteen thousand, three hundred one".