13011100323233 has 4 divisors (see below), whose sum is σ = 13011299277360. Its totient is φ = 13010901369108.

The previous prime is 13011100323229. The next prime is 13011100323259. The reversal of 13011100323233 is 33232300111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13011100323233 - 2² = 13011100323229 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011100323199 and 13011100323208.

It is not an unprimeable number, because it can be changed into a prime (13011100323223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99378935 + ... + 99509772.

It is an arithmetic number, because the mean of its divisors is an integer number (3252824819340).

Almost surely, 2^{13011100323233} is an apocalyptic number.

It is an amenable number.

13011100323233 is a deficient number, since it is larger than the sum of its proper divisors (198954127).

13011100323233 is an equidigital number, since it uses as much as digits as its factorization.

13011100323233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198954126.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13011100323233 its reverse (33232300111031), we get a palindrome (46243400434264).

The spelling of 13011100323233 in words is "thirteen trillion, eleven billion, one hundred million, three hundred twenty-three thousand, two hundred thirty-three".