Base | Representation |
---|---|
bin | 10010111011110000010… |
… | …101001100011100001011 |
3 | 11121101101202011122011222 |
4 | 102323300111030130023 |
5 | 132304134211224321 |
6 | 2433420034112255 |
7 | 163000526213561 |
oct | 22736025143413 |
9 | 4541352148158 |
10 | 1301112211211 |
11 | 461886a17a0a |
12 | 1901b7a1b68b |
13 | 95904662297 |
14 | 46d8d185a31 |
15 | 23ca18be3ab |
hex | 12ef054c70b |
1301112211211 has 4 divisors (see below), whose sum is σ = 1302092704032. Its totient is φ = 1300131718392.
The previous prime is 1301112211187. The next prime is 1301112211213. The reversal of 1301112211211 is 1121122111031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1301112211211 - 214 = 1301112194827 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1301112211211.
It is not an unprimeable number, because it can be changed into a prime (1301112211213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 490244420 + ... + 490247073.
It is an arithmetic number, because the mean of its divisors is an integer number (325523176008).
Almost surely, 21301112211211 is an apocalyptic number.
1301112211211 is a deficient number, since it is larger than the sum of its proper divisors (980492821).
1301112211211 is an equidigital number, since it uses as much as digits as its factorization.
1301112211211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 980492820.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1301112211211 its reverse (1121122111031), we get a palindrome (2422234322242).
The spelling of 1301112211211 in words is "one trillion, three hundred one billion, one hundred twelve million, two hundred eleven thousand, two hundred eleven".
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