130111320320023 has 4 divisors (see below), whose sum is σ = 148698651794320. Its totient is φ = 111523988845728.

The previous prime is 130111320319969. The next prime is 130111320320063. The reversal of 130111320320023 is 320023023111031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130111320320023 - 2¹³ = 130111320311831 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130111320319976 and 130111320320003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130111320320063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9293665737138 + ... + 9293665737151.

It is an arithmetic number, because the mean of its divisors is an integer number (37174662948580).

Almost surely, 2^{130111320320023} is an apocalyptic number.

130111320320023 is a deficient number, since it is larger than the sum of its proper divisors (18587331474297).

130111320320023 is an equidigital number, since it uses as much as digits as its factorization.

130111320320023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18587331474296.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 130111320320023 its reverse (320023023111031), we get a palindrome (450134343431054).

The spelling of 130111320320023 in words is "one hundred thirty trillion, one hundred eleven billion, three hundred twenty million, three hundred twenty thousand, twenty-three".