13011140431 has 4 divisors (see below), whose sum is σ = 13031439264. Its totient is φ = 12990841600.

The previous prime is 13011140407. The next prime is 13011140437. The reversal of 13011140431 is 13404111031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13011140431 - 2⁵ = 13011140399 is a prime.

It is a super-2 number, since 2×13011140431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011140399 and 13011140408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011140437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10148455 + ... + 10149736.

It is an arithmetic number, because the mean of its divisors is an integer number (3257859816).

Almost surely, 2^13011140431 is an apocalyptic number.

13011140431 is a deficient number, since it is larger than the sum of its proper divisors (20298833).

13011140431 is an equidigital number, since it uses as much as digits as its factorization.

13011140431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20298832.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13011140431 its reverse (13404111031), we get a palindrome (26415251462).

The spelling of 13011140431 in words is "thirteen billion, eleven million, one hundred forty thousand, four hundred thirty-one".