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1301114321211 = 3433704773737
BaseRepresentation
bin10010111011110000011…
…101001111100100111011
311121101101220010211120010
4102323300131033210323
5132304140231234321
62433420151233003
7163000553152305
oct22736035174473
94541356124503
101301114321211
11461888129211
121901b8678763
1395904c207c3
1446d8d574975
1523ca1b89676
hex12ef074f93b

1301114321211 has 4 divisors (see below), whose sum is σ = 1734819094952. Its totient is φ = 867409547472.

The previous prime is 1301114321207. The next prime is 1301114321267. The reversal of 1301114321211 is 1121234111031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1301114321211 - 22 = 1301114321207 is a prime.

It is a super-2 number, since 2×13011143212112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1301114321411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216852386866 + ... + 216852386871.

It is an arithmetic number, because the mean of its divisors is an integer number (433704773738).

Almost surely, 21301114321211 is an apocalyptic number.

1301114321211 is a deficient number, since it is larger than the sum of its proper divisors (433704773741).

1301114321211 is an equidigital number, since it uses as much as digits as its factorization.

1301114321211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 433704773740.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 1301114321211 its reverse (1121234111031), we get a palindrome (2422348432242).

The spelling of 1301114321211 in words is "one trillion, three hundred one billion, one hundred fourteen million, three hundred twenty-one thousand, two hundred eleven".

Divisors: 1 3 433704773737 1301114321211