Base | Representation |
---|---|
bin | 11101100101011000010000… |
… | …001101110110101001101010 |
3 | 122001200120211210002112020011 |
4 | 131211120100031312221222 |
5 | 114023223344400112302 |
6 | 1140420344405322134 |
7 | 36256165635262264 |
oct | 3545302015665152 |
9 | 561616753075204 |
10 | 130112011332202 |
11 | 38504215424a59 |
12 | 127146b540634a |
13 | 577a682696493 |
14 | 241b65254ab34 |
15 | 10097a30415d7 |
hex | 765610376a6a |
130112011332202 has 4 divisors (see below), whose sum is σ = 195168016998306. Its totient is φ = 65056005666100.
The previous prime is 130112011332101. The next prime is 130112011332211. The reversal of 130112011332202 is 202233110211031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 128682501756561 + 1429509575641 = 11343831^2 + 1195621^2 .
It is a super-2 number, since 2×1301120113322022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32528002833049 + ... + 32528002833052.
Almost surely, 2130112011332202 is an apocalyptic number.
130112011332202 is a deficient number, since it is larger than the sum of its proper divisors (65056005666104).
130112011332202 is an equidigital number, since it uses as much as digits as its factorization.
130112011332202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65056005666103.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 130112011332202 its reverse (202233110211031), we get a palindrome (332345121543233).
The spelling of 130112011332202 in words is "one hundred thirty trillion, one hundred twelve billion, eleven million, three hundred thirty-two thousand, two hundred two".
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