Base | Representation |
---|---|
bin | 1011110101010110100100… |
… | …1010001010000111101010 |
3 | 1201001212020022022021001112 |
4 | 2331111221022022013222 |
5 | 3201133434333211104 |
6 | 43401134432350322 |
7 | 2512013110664345 |
oct | 275255112120752 |
9 | 51055208267045 |
10 | 13011220210154 |
11 | 4167033674751 |
12 | 15617b33a53a2 |
13 | 734c503c501a |
14 | 32da6425945c |
15 | 1786b972386e |
hex | bd56928a1ea |
13011220210154 has 8 divisors (see below), whose sum is σ = 19992850566948. Its totient is φ = 6346936687840.
The previous prime is 13011220210151. The next prime is 13011220210159. The reversal of 13011220210154 is 45101202211031.
13011220210154 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 12091107609529 + 920112600625 = 3477227^2 + 959225^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13011220210151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79336708517 + ... + 79336708680.
Almost surely, 213011220210154 is an apocalyptic number.
13011220210154 is a deficient number, since it is larger than the sum of its proper divisors (6981630356794).
13011220210154 is a wasteful number, since it uses less digits than its factorization.
13011220210154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158673417240.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 13011220210154 its reverse (45101202211031), we get a palindrome (58112422421185).
The spelling of 13011220210154 in words is "thirteen trillion, eleven billion, two hundred twenty million, two hundred ten thousand, one hundred fifty-four".
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