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13011230002 = 26505615001
BaseRepresentation
bin11000001111000011…
…11001110100110010
31020120202220222010111
430013201321310302
5203121333330002
65551031451534
7640300426111
oct140741716462
936522828114
1013011230002
115577555751
122631526baa
1312c4804384
148b604dc78
1551241e3d7
hex307879d32

13011230002 has 4 divisors (see below), whose sum is σ = 19516845006. Its totient is φ = 6505615000.

The previous prime is 13011229951. The next prime is 13011230003. The reversal of 13011230002 is 20003211031.

13011230002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20003211031 = 68669291299.

It can be written as a sum of positive squares in only one way, i.e., 7698132121 + 5313097881 = 87739^2 + 72891^2 .

It is not an unprimeable number, because it can be changed into a prime (13011230003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3252807499 + ... + 3252807502.

Almost surely, 213011230002 is an apocalyptic number.

13011230002 is a deficient number, since it is larger than the sum of its proper divisors (6505615004).

13011230002 is an equidigital number, since it uses as much as digits as its factorization.

13011230002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6505615003.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13011230002 its reverse (20003211031), we get a palindrome (33014441033).

The spelling of 13011230002 in words is "thirteen billion, eleven million, two hundred thirty thousand, two".

Divisors: 1 2 6505615001 13011230002