Base | Representation |
---|---|
bin | 11000001111000100… |
… | …01011011001101101 |
3 | 1020120210001121212222 |
4 | 30013202023121231 |
5 | 203121343130442 |
6 | 5551033205125 |
7 | 640301146031 |
oct | 140742133155 |
9 | 36523047788 |
10 | 13011301997 |
11 | 55775a4851 |
12 | 26315607a5 |
13 | 12c482b085 |
14 | 8b606c1c1 |
15 | 5124358d2 |
hex | 30788b66d |
13011301997 has 4 divisors (see below), whose sum is σ = 13068620736. Its totient is φ = 12953983260.
The previous prime is 13011301993. The next prime is 13011302027. The reversal of 13011301997 is 79910311031.
13011301997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13011301997 - 22 = 13011301993 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13011301991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28659029 + ... + 28659482.
It is an arithmetic number, because the mean of its divisors is an integer number (3267155184).
Almost surely, 213011301997 is an apocalyptic number.
It is an amenable number.
13011301997 is a deficient number, since it is larger than the sum of its proper divisors (57318739).
13011301997 is an equidigital number, since it uses as much as digits as its factorization.
13011301997 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57318738.
The product of its (nonzero) digits is 5103, while the sum is 35.
The spelling of 13011301997 in words is "thirteen billion, eleven million, three hundred one thousand, nine hundred ninety-seven".
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