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13011302033 = 51472527939
BaseRepresentation
bin11000001111000100…
…01011011010010001
31020120210001121221022
430013202023122101
5203121343131113
65551033205225
7640301146112
oct140742133221
936523047838
1013011302033
1155775a4884
122631560815
1312c482b0b2
148b606c209
15512435908
hex30788b691

13011302033 has 4 divisors (see below), whose sum is σ = 13013835120. Its totient is φ = 13008768948.

The previous prime is 13011302027. The next prime is 13011302047. The reversal of 13011302033 is 33020311031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33020311031 = 231435665697.

It is a cyclic number.

It is not a de Polignac number, because 13011302033 - 26 = 13011301969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13011302093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1258823 + ... + 1269116.

It is an arithmetic number, because the mean of its divisors is an integer number (3253458780).

Almost surely, 213011302033 is an apocalyptic number.

It is an amenable number.

13011302033 is a deficient number, since it is larger than the sum of its proper divisors (2533087).

13011302033 is an equidigital number, since it uses as much as digits as its factorization.

13011302033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2533086.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 13011302033 its reverse (33020311031), we get a palindrome (46031613064).

The spelling of 13011302033 in words is "thirteen billion, eleven million, three hundred two thousand, thirty-three".

Divisors: 1 5147 2527939 13011302033