Base | Representation |
---|---|
bin | 10010111011110001011… |
… | …001111111000101000101 |
3 | 11121101110000002211002122 |
4 | 102323301121333011011 |
5 | 132304203320310141 |
6 | 2433421520415325 |
7 | 163001135411540 |
oct | 22736131770505 |
9 | 4541400084078 |
10 | 1301130244421 |
11 | 461896114597 |
12 | 190201a77545 |
13 | 95908307417 |
14 | 46d9171b857 |
15 | 23ca328264b |
hex | 12ef167f145 |
1301130244421 has 8 divisors (see below), whose sum is σ = 1487048942400. Its totient is φ = 1115222283648.
The previous prime is 1301130244373. The next prime is 1301130244433. The reversal of 1301130244421 is 1244420311031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1301130244421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1301130246421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2422931 + ... + 2910816.
It is an arithmetic number, because the mean of its divisors is an integer number (185881117800).
Almost surely, 21301130244421 is an apocalyptic number.
It is an amenable number.
1301130244421 is a deficient number, since it is larger than the sum of its proper divisors (185918697979).
1301130244421 is an equidigital number, since it uses as much as digits as its factorization.
1301130244421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5368603.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1301130244421 its reverse (1244420311031), we get a palindrome (2545550555452).
The spelling of 1301130244421 in words is "one trillion, three hundred one billion, one hundred thirty million, two hundred forty-four thousand, four hundred twenty-one".
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