1301131033 has 4 divisors (see below), whose sum is σ = 1328814720. Its totient is φ = 1273447348.

The previous prime is 1301130983. The next prime is 1301131043. The reversal of 1301131033 is 3301311031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3301311031 = 7103 ⋅464777.

It is a cyclic number.

It is not a de Polignac number, because 1301131033 - 2¹³ = 1301122841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301130998 and 1301131016.

It is not an unprimeable number, because it can be changed into a prime (1301131043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13841773 + ... + 13841866.

It is an arithmetic number, because the mean of its divisors is an integer number (332203680).

Almost surely, 2^1301131033 is an apocalyptic number.

It is an amenable number.

1301131033 is a deficient number, since it is larger than the sum of its proper divisors (27683687).

1301131033 is an equidigital number, since it uses as much as digits as its factorization.

1301131033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27683686.

The product of its (nonzero) digits is 81, while the sum is 16.

The square root of 1301131033 is about 36071.1939502978. The cubic root of 1301131033 is about 1091.7093044849.

Adding to 1301131033 its reverse (3301311031), we get a palindrome (4602442064).

It can be divided in two parts, 13011 and 31033, that added together give a palindrome (44044).

The spelling of 1301131033 in words is "one billion, three hundred one million, one hundred thirty-one thousand, thirty-three".