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130113113232332 = 2268473147505193
BaseRepresentation
bin11101100101011001010001…
…111001010001001111001100
3122001200200200120111212001002
4131211121101321101033030
5114023233123441413312
61140421050011035432
736256235145261146
oct3545312171211714
9561620616455032
10130113113232332
113850473041791a
121271496243bb78
13577a7c9a60ca9
14241b718a21c96
151009819b504c2
hex765651e513cc

130113113232332 has 12 divisors (see below), whose sum is σ = 227698285486056. Its totient is φ = 65056460236320.

The previous prime is 130113113232331. The next prime is 130113113232373. The reversal of 130113113232332 is 233232311311031.

It is a junction number, because it is equal to n+sod(n) for n = 130113113232295 and 130113113232304.

It is not an unprimeable number, because it can be changed into a prime (130113113232331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21013673 + ... + 26491520.

It is an arithmetic number, because the mean of its divisors is an integer number (18974857123838).

Almost surely, 2130113113232332 is an apocalyptic number.

It is an amenable number.

130113113232332 is a deficient number, since it is larger than the sum of its proper divisors (97585172253724).

130113113232332 is a wasteful number, since it uses less digits than its factorization.

130113113232332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48189928 (or 48189926 counting only the distinct ones).

The product of its (nonzero) digits is 5832, while the sum is 29.

Adding to 130113113232332 its reverse (233232311311031), we get a palindrome (363345424543363).

The spelling of 130113113232332 in words is "one hundred thirty trillion, one hundred thirteen billion, one hundred thirteen million, two hundred thirty-two thousand, three hundred thirty-two".

Divisors: 1 2 4 684731 1369462 2738924 47505193 95010386 190020772 32528278308083 65056556616166 130113113232332