13011312121 has 4 divisors (see below), whose sum is σ = 13011560100. Its totient is φ = 13011064144.

The previous prime is 13011312109. The next prime is 13011312131. The reversal of 13011312121 is 12121311031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12121311031 = 4397 ⋅2756723.

It can be written as a sum of positive squares in 2 ways, for example, as 7540490896 + 5470821225 = 86836^2 + 73965^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011312121 - 2⁵ = 13011312089 is a prime.

It is a super-2 number, since 2×13011312121² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13011312095 and 13011312104.

It is not an unprimeable number, because it can be changed into a prime (13011312131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10906 + ... + 161683.

It is an arithmetic number, because the mean of its divisors is an integer number (3252890025).

Almost surely, 2^13011312121 is an apocalyptic number.

It is an amenable number.

13011312121 is a deficient number, since it is larger than the sum of its proper divisors (247979).

13011312121 is an equidigital number, since it uses as much as digits as its factorization.

13011312121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 247978.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 13011312121 its reverse (12121311031), we get a palindrome (25132623152).

The spelling of 13011312121 in words is "thirteen billion, eleven million, three hundred twelve thousand, one hundred twenty-one".