Base | Representation |
---|---|
bin | 111100100101101011… |
… | …0001010111111111111 |
3 | 110102211210210110020202 |
4 | 1321023112022333333 |
5 | 4112432424403203 |
6 | 135434555434115 |
7 | 12254216201663 |
oct | 1711326127777 |
9 | 412753713222 |
10 | 130113122303 |
11 | 501a951363a |
12 | 2127275593b |
13 | c3674610c8 |
14 | 64245148a3 |
15 | 35b7c5b388 |
hex | 1e4b58afff |
130113122303 has 4 divisors (see below), whose sum is σ = 130180505448. Its totient is φ = 130045739160.
The previous prime is 130113122297. The next prime is 130113122317. The reversal of 130113122303 is 303221311031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303221311031 = 1237 ⋅245126363.
It is a cyclic number.
It is not a de Polignac number, because 130113122303 - 26 = 130113122239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130113122353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33688676 + ... + 33692537.
It is an arithmetic number, because the mean of its divisors is an integer number (32545126362).
Almost surely, 2130113122303 is an apocalyptic number.
130113122303 is a deficient number, since it is larger than the sum of its proper divisors (67383145).
130113122303 is an equidigital number, since it uses as much as digits as its factorization.
130113122303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67383144.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 130113122303 its reverse (303221311031), we get a palindrome (433334433334).
The spelling of 130113122303 in words is "one hundred thirty billion, one hundred thirteen million, one hundred twenty-two thousand, three hundred three".
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