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130113200013 = 3617253127773
BaseRepresentation
bin111100100101101011…
…0011101111110001101
3110102211210221101211220
41321023112131332031
54112432434400023
6135435001233553
712254216644356
oct1711326357615
9412753841756
10130113200013
11501a9566a65
12212727928b9
13c36748a5a4
146424534d2d
1535b7c743e3
hex1e4b59df8d

130113200013 has 16 divisors (see below), whose sum is σ = 173840354496. Its totient is φ = 86564213120.

The previous prime is 130113200011. The next prime is 130113200023. The reversal of 130113200013 is 310002311031.

It is a cyclic number.

It is not a de Polignac number, because 130113200013 - 21 = 130113200011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130113199965 and 130113200001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130113200011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4670995 + ... + 4698767.

It is an arithmetic number, because the mean of its divisors is an integer number (10865022156).

Almost surely, 2130113200013 is an apocalyptic number.

It is an amenable number.

130113200013 is a deficient number, since it is larger than the sum of its proper divisors (43727154483).

130113200013 is a wasteful number, since it uses less digits than its factorization.

130113200013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30924.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 130113200013 its reverse (310002311031), we get a palindrome (440115511044).

The spelling of 130113200013 in words is "one hundred thirty billion, one hundred thirteen million, two hundred thousand, thirteen".

Divisors: 1 3 617 1851 2531 7593 27773 83319 1561627 4684881 17135941 51407823 70293463 210880389 43371066671 130113200013